Knowledgebase, relied on by millions of students &آلة حاسبة لمجال دالّة تجد مجال دالّة خطوة بخطوة0 is the domain This consists of all points in the plane except (0;0) This is an open set The range of the function is (1 ;1) Here is a skecth of the level curves f = 1, f = 0, and f = 1
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Find and sketch the domain of the function f(x y)=ln(x^2+y^2-2)
Find and sketch the domain of the function f(x y)=ln(x^2+y^2-2)-Popular Problems Algebra Find the Domain and Range y=x^2 y = x2 y = x 2 The domain of the expression is all real numbers except where the expression is undefined In this case, there is no real number that makes the expression undefined Interval Notation (−∞,∞) ( ∞, ∞) SetSince et is increasing, f(0;0) = 0 is the smallest possible value for fOn the other hand, by increasing x or y appropriately, we may make the
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Fresh_42 said In this case you don't have to deal with negative numbers, because the squares are always positive ( − 1) 2 = 1 Therefore only ( x, y) = ( 0, 0) can violate this condition So here x 2 y 2 >View this answer Given the function, f (x,y) = √x2y2−1ln(4−x2−y2) √xy its definition domain if found See full answer below≤ 3 This domain is all ordered pairs (x, y) on the annulus that is centered on the origin, and has inner radius 1 and outer radius √ (3) (b)
This question is most certainly asking about domain!The minimum value of f (x, y) = x 2 y 2 f (x, y) = x 2 y 2 is zero (attained when x = y = 0) x = y = 0) When x = 0, x = 0, the function becomes z = y 2, z = y 2, and when y = 0, y = 0, then the function becomes z = x 2 z = x 2 These are crosssections of the graph, and are parabolas Recall from Introduction to Vectors in Space thatSo f(x;y) is defined only if x2 y2 0 In other words, the domain is x2 y2 0 Note that x2 y2 = (x y)(x y) = 0 Therefore the boundary is the union of two diagonal lines passing through the origin The domain does contain the boundaries Sketch the graph of f(x;y) = e y Because the function f(x;y) does not depends on x, the section of
2) The domain of arcsin (t) is 1, 1 1 ≤ x²Check out a sample textbook solution See solution arrow, ≤ , ≥ * The inequality sign ≤ is entered as the pair of consecutive
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4g This is an annular region in the xyplane (b) f(x;y) = p x p yThe domain of the function f(x,y) = ln(x2 y2−100) f ( x, y) = ln ( x 2 y 2 − 100) is represented by the set of points (x,y) such that the argument of the See full answer belowFind the domain of the function f(x,y)=ln(x^2y^24)!
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Answers and Replies You are correct The domain is the number plane excluding only the point (0,0) (the 'origin') The equation x 2 y 2 = 0 can be thought of as a degenerate circle whose center is at (0, 0) and whose radius is 0 In other words, the point (0, 0)Safety How worksY(x)=ln(x²) 1 Domain real log requires positive arguments ln(x²) ⇒ x²
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The area of a function (the main important area) continuously would nicely be chanced on stating restrictthis would nicely be a rational functio and the denominator isn't allowed to be 0So then the restrict is x is different of 0 which make the area {xbelongs to actual variety set x different from 0 for finding out to purchase the diversity there are few procedures you are able to graph the functin it is y= a million/xDomain\f (x)=x^3 domain\f (x)=\ln (x5) domain\f (x)=\frac {1} {x^2} domain\y=\frac {x} {x^26x8} domain\f (x)=\sqrt {x3} domain\f (x)=\cos (2x5) domain\f (x)=\sin (3x) precalculusfunctiondomaincalculator enℂ then the domain is all possible numbers of the set If you start out with ℝ then any real number squared is a positive number, and a square root function is defined fo
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2 The domain is all values of x x that make the expression defined Interval NotationCompute answers using Wolfram's breakthrough technology &Assuming both f and square root are being defined for either ℝ>ℝ or for ℂ >
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